Mysql查询及删除重复记录的方法大全


有一些数据重复了,需要整理出来,删除重复记录,网上查了下资料,收集一下,但还没有测试过,不知道有没有效,记录备查。

1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断
 
select * from people
where peopleId in (select  peopleId  from  people  group  by  peopleId  having  count(peopleId) > 1)

2、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录

delete from people
where peopleId  in (select  peopleId  from people  group  by  peopleId   having  count(peopleId) > 1)
and rowid not in (select min(rowid) from  people  group by peopleId  having count(peopleId )>1)

3、查找表中多余的重复记录(多个字段)
select * from vitae a
where (a.peopleId,a.seq) in  (select peopleId,seq from vitae group by peopleId,seq  having count(*) > 1)

4、删除表中多余的重复记录(多个字段),只留有rowid最小的记录 (可用)
delete from vitae a
where (a.peopleId,a.seq) in  (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

注意:最外层的表不能用别名,否则报错。

DELETE
FROM TABLEA  
WHERE id not in (
SELECT min(e.id)
FROM (SELECT t1.id FROM TABLEA t1 GROUP BY t1.title HAVING count(t1.title) > 1) e
)
and title in (
SELECT r.title
FROM ( SELECT t2.title FROM TABLEA t2 GROUP BY t2.title HAVING count(t2.title) > 1) r
)


5、查找表中多余的重复记录(多个字段),不包含rowid最小的记录
select * from vitae a
where (a.peopleId,a.seq) in  (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

(二)
比方说
在A表中存在一个字段“name”,
而且不同记录之间的“name”值有可能会相同,
现在就是需要查询出在该表中的各记录之间,“name”值存在重复的项;
Select Name,Count(*) From tabelA Group By Name Having Count(*) > 1

如果还查性别也相同大则如下:
Select Name,sex,Count(*) From tableA Group By Name,sex Having Count(*) > 1

(三)
方法一

declare @max integer,@id integer

declare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) >; 1

open cur_rows

fetch cur_rows into @id,@max

while @@fetch_status=0

begin

select @max = @max -1

set rowcount @max

delete from 表名 where 主字段 = @id

fetch cur_rows into @id,@max
end

close cur_rows

set rowcount 0

方法二

"重复记录"有两个意义上的重复记录,一是完全重复的记录,也即所有字段均重复的记录,二是部分关键字段重复的记录,比如Name字段重复,而其他字段不一定重复或都重复可以忽略。

  1、对于第一种重复,比较容易解决,使用

select distinct * from tableName

  就可以得到无重复记录的结果集。

查询不同name值的记录条数,select count(distinct(name))  from tableName  

  如果该表需要删除重复的记录(重复记录保留1条),可以按以下方法删除

select distinct * into #Tmp from tableName

drop table tableName

select * into tableName from #Tmp
drop table #Tmp

  发生这种重复的原因是表设计不周产生的,增加唯一索引列即可解决。

  2、这类重复问题通常要求保留重复记录中的第一条记录,操作方法如下

  假设有重复的字段为Name,Address,要求得到这两个字段唯一的结果集

select identity(int,1,1) as autoID, * into #Tmp from tableName

select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID

select * from #Tmp where autoID in(select autoID from #tmp2)

  最后一个select即得到了Name,Address不重复的结果集(但多了一个autoID字段,实际写时可以写在select子句中省去此列)

(四) 查询重复

select * from tablename where id in (select id from tablename
group by id
having count(id) > 1
)


SQL Server数据库多种方式查找重复记录:

示例:表stuinfo,有三个字段recno(自增),stuid,stuname

建该表的Sql语句如下:

CREATE TABLE [StuInfo] (

[recno] [int] IDENTITY (1, 1) NOT NULL ,

[stuid] [varchar] (10) COLLATE Chinese_PRC_CI_AS NOT NULL ,

[stuname] [varchar] (10) COLLATE Chinese_PRC_CI_AS NOT NULL

) ON [PRIMARY]

GO

1.查某一列(或多列)的重复值(只可以查出重复记录的值,不能查出整个记录的信息)

例如:查找stuid,stuname重复的记录

select stuid,stuname from stuinfo

group by stuid,stuname

having(count(*))>1

2.查某一列有重复值的记录(此方法查出的是所有重复的记录,如果有两条记录重复的,就查出两条)


例如:查找stuid重复的记录

select * from stuinfo

where stuid in (

select stuid from stuinfo

group by stuid

having(count(*))>1

)

3.查某一列有重复值的记录(只显示多余的记录,也就是说如果有三条记录重复的,就显示两条)

前提:需有一个不重复的列,此示例为recno。

例如:查找stuid重复的记录

select * from stuinfo s1

where recno not in (

select max(recno) from stuinfo s2

where s1.stuid=s2.stuid


参考:http://www.cnblogs.com/jzaileen/archive/2008/08/29/1279346.html

http://www.knowsky.com/397948.html

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